dot(a, b, out=None)
openfermion.utils.channel_state.dot()
Dot product of two arrays. Specifically,
If both
aandbare 1-D arrays, it is inner product of vectors (without complex conjugation).If both
aandbare 2-D arrays, it is matrix multiplication, but using :func:matmulora @ bis preferred.If either
aorbis 0-D (scalar), it is equivalent to :func:multiplyand usingnumpy.multiply(a, b)ora * bis preferred.If
ais an N-D array andbis a 1-D array, it is a sum product over the last axis ofaandb.If
ais an N-D array andbis an M-D array (whereM>=2), it is a sum product over the last axis ofaand the second-to-last axis ofb::dot(a, b)[i,j,k,m] = sum(a[i,j,:] * b[k,:,m])
It uses an optimized BLAS library when possible (see numpy.linalg).
Parameters
a : array_like
First argument.
b : array_like
Second argument.
out : ndarray, optional
Output argument. This must have the exact kind that would be returned
if it was not used. In particular, it must have the right type, must be
C-contiguous, and its dtype must be the dtype that would be returned
for dot(a,b). This is a performance feature. Therefore, if these
conditions are not met, an exception is raised, instead of attempting
to be flexible.
Returns
output : ndarray
Returns the dot product of a and b. If a and b are both
scalars or both 1-D arrays then a scalar is returned; otherwise
an array is returned.
If out is given, then it is returned.
Raises
ValueError
If the last dimension of a is not the same size as
the second-to-last dimension of b.
See Also
vdot : Complex-conjugating dot product. vecdot : Vector dot product of two arrays. tensordot : Sum products over arbitrary axes. einsum : Einstein summation convention. matmul : '@' operator as method with out parameter. linalg.multi_dot : Chained dot product.
Examples
>>> import numpy as np
>>> np.dot(3, 4)
12
Neither argument is complex-conjugated:
np.dot([2j, 3j], [2j, 3j])(-13+0j)
For 2-D arrays it is the matrix product:
a = [[1, 0], [0, 1]]b = [[4, 1], [2, 2]]np.dot(a, b)array([[4, 1],[2, 2]])
a = np.arange(3*4*5*6).reshape((3,4,5,6))b = np.arange(3*4*5*6)[::-1].reshape((5,4,6,3))np.dot(a, b)[2,3,2,1,2,2]499128sum(a[2,3,2,:] * b[1,2,:,2])499128